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If $A=\begin{bmatrix}3& 6&24\\12 & 9&36\\6… | ClassNotes
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Sep 18, 2022
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If $A=\begin{bmatrix}3& 6&24\\12 & 9&36\\6 &15 &18\end{bmatrix}$ then 1/3A=
Difficulty: Easy
A:
$\begin{bmatrix}9& 18&72\\36 & 27&108\\18 &45 &54\end{bmatrix}$
B:
$\begin{bmatrix}1& 2&8\\4 & 4&12\\3 &5 &6\end{bmatrix}$
C:
$\begin{bmatrix}1& 2&8\\4 & 3&12\\2 &5 &6\end{bmatrix}$
D:
$\begin{bmatrix}1& 2&18\\4 & 3&12\\3 &5 &6\end{bmatrix}$
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ID: 63273dbaca83163ac3a11b5f
