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If $f(x)=\frac{1}{\sqrt{x^{2}-1}}$, then… | ClassNotes
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Sep 18, 2022
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If $f(x)=\frac{1}{\sqrt{x^{2}-1}}$, then f'(x) equals:
Difficulty: Easy
A:
$\frac{2}{\sqrt{x^{2}-1}}$
B:
$-\frac{x}{\sqrt{(x^{2}-1)^{3}}}$
C:
$\frac{x}{\sqrt{x^{2}-1}}$
D:
$\frac{3x}{\sqrt{x^{2}-1}}$
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ID: 63273db8ca83163ac3a102c3
